If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x^2+62x+42=0
a = 6; b = 62; c = +42;
Δ = b2-4ac
Δ = 622-4·6·42
Δ = 2836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2836}=\sqrt{4*709}=\sqrt{4}*\sqrt{709}=2\sqrt{709}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-2\sqrt{709}}{2*6}=\frac{-62-2\sqrt{709}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+2\sqrt{709}}{2*6}=\frac{-62+2\sqrt{709}}{12} $
| -7j=56 | | r+3.4=7.9 | | a=4a-124 | | 2y-5=3y-11 | | -16=m10 | | X+(x+11)+(x+22)=363 | | X+(x+10)=0 | | (3-2x/5)=15 | | 3.2x^2+2.4x=5 | | 10^(2x)=9.8 | | -x^2+256=0 | | 32/x=0.77 | | 1.6=x/7+2.6 | | 5(x-4))-4(x+1)=0 | | 16=2^6x+1 | | 85-a=23 | | 15-a=23 | | 0.35*0.15=x | | .9x=133 | | 14x-1=5x-7 | | 3x(3x-5)+(4x+3)=62 | | 9-5d+8d=4 | | (2z-3)/5=1/2 | | (15)=350/x | | a/4+18=2a-10 | | (2*8)+(y-4)=36 | | 4w+12=9w+38 | | 3x-10+2x+45=180 | | 12x+39x=177 | | a=0.36 | | 11^2x=14.641 | | A=40-4x^2 |